4/x^2=29

Solution for 4/x^2=29 equation:

4/x^2=29

We move all terms to the left:

4/x^2-(29)=0


Domain of the equation: x^2!=0

x^2!=0/

x^2!=√0

x!=0

x∈R


We multiply all the terms by the denominator


-29*x^2+4=0

We add all the numbers together, and all the variables

-29x^2+4=0

a = -29; b = 0; c = +4;
Δ = b2-4ac
Δ = 02-4·(-29)·4
Δ = 464
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{464}=\sqrt{16*29}=\sqrt{16}*\sqrt{29}=4\sqrt{29}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{29}}{2*-29}=\frac{0-4\sqrt{29}}{-58}
=-\frac{4\sqrt{29}}{-58}
=-\frac{2\sqrt{29}}{-29}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{29}}{2*-29}=\frac{0+4\sqrt{29}}{-58}
=\frac{4\sqrt{29}}{-58}
=\frac{2\sqrt{29}}{-29}
$